We know, W = F * s
W = mg * s
Here, w = 2 J
m = 180 g = 0.180 Kg
g = 9.8 m/s
Substitute their values into the expression:
2 = 0.180*9.8 * s
1.764s = 2
s = 2 / 1.764
s = 1.13 meter
In short, Your Final Answer is 1.13 m
Hope this helps!
Answer:
227 m/s
Explanation:
Kinetic energy formula:
- where m = mass of the object (kg)
- and v = speed of the object (m/s)
Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.
First convert the mass to kilograms:
Plug known values into the KE formula.
Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.
First convert the mass to kilograms:
Plug known values into the KE formula.
The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.
<span>try y =kx
and find value of k
by substituing x and y from the table</span>
-- The two 8-ohm resistors in parallel are equivalent to
a single 4-ohm resistor.
-- The current in the circuit is
(voltage) / (resistance) = (9v) / (4ohms) = 2.25 Amperes
-- If another resistor is added in parallel, then no matter how large
or small it is, the current in the circuit increases.
(When another lane is added to a road, the traffic capacity of the
road increases.)
The circuit is now equivalent to a 12.5-ohm resistor in parallel
with 4-ohms. That's ...
(12.5 x 4) / (12.5 + 4) = 50/16.5 = 3.03 ohms .
-- The new current is (9v) / (3.03 ohms) = 2.97 Amperes
Answer:
No, its not reasonable.
Explanation:
The substance that is to be dissolved is known as solute. The substance that is dissolving is known as solvent.
The amount of solvent in the mixture should be greater than that of solute.
Suppose we are taking a solvent in a beaker and we are continuously adding solute in it. Initially the solute dissolve quickly. At some point the solute stops dissolving in the solvent. This is known as saturation point of the solvent. After saturation point if solute is added further it does not dissolve in the solvent.
So, its not possible to dissolve 12.8 g of one substance in 11 g of another.
