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Rina8888 [55]
3 years ago
8

density is the ratio of mass to volume density = mass/volume compare the density of different liquids with the same volume the l

iquid with the greatest density is ____ the liquid wity the least density is ____
Mathematics
1 answer:
bija089 [108]3 years ago
7 0

Here, we are required to compare the density of different liquids with the same volume

Since density is the ratio of mass to volume, different liquids for example, kerosene and water if they have the same volume, will have different masses.

This is due to the difference in their densities.

Therefore, according to the statement in the question above;

While comparing the density of Liquids with the same volume, the liquid with the greatest density is heavier(more quantity of matter per unit volume) while the liquid with the least density is lighter( less quantity of matter per unit volume).

Read more:

brainly.com/question/17826958

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Answer:

The answer would be c

Step-by-step explanation:

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Jarius placed 6 number tiles labelled 4, 7, 10, 11, 14, and 21 in a box. He will pick one of the number tiles from the box witho
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Answer:

1/2

Step-by-step explanation:

The possible picks are 4,7,10,11,14,21

The even tiles are 4,10,14

P(even) = number of even tiles /total tiles

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Sand pouring from a chute forms a conical pile whose height is always equal to the diameter. If the height increases at a consta
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Answer:

125\pi \frac{\text{ft}^3}{\text{min}}.

Step-by-step explanation:

Let x represent height of the cone.

We have been given that Sand pouring from a chute forms a conical pile whose height is always equal to the diameter.

We know that radius is half the diameter, so radius of cone would be \frac{x}{2}.

We will use volume of cone formula to solve our given problem.

V=\frac{1}{3}\pi r^2h

Upon substituting the value of height and radius in terms of x, we will get:

V=\frac{1}{3}\pi (\frac{x}{2})^2(x)

V=\frac{1}{3}\pi\frac{x^2}{4}(x)

V=\frac{1}{12}\pi x^3

Now, we will take the derivative of volume with respect to time as:

\frac{dV}{dt}=\frac{1}{12}\pi\cdot 3x^2\cdot \frac{dx}{dt}

\frac{dV}{dt}=\frac{1}{4}\pi\cdot x^2\cdot \frac{dx}{dt}

Upon substituting x=10 and \frac{dx}{dt}=5, we will get:

\frac{dV}{dt}=\frac{1}{4}\pi\cdot (10)^2\cdot 5

\frac{dV}{dt}=\frac{1}{4}\pi\cdot 100\cdot 5

\frac{dV}{dt}=\pi\cdot 25\cdot 5

\frac{dV}{dt}=125\pi

Therefore, the sand is pouring from the chute at a rate of 125\pi \frac{\text{ft}^3}{\text{min}}.

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3 years ago
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Answer:

an angle supplementary to angle 3 is 125

Step-by-step explanation:

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