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3 years ago

4. If angle 2 = angle 3 and m angle 2= 55, find the measure of angle that is supplementary to angle 3.

Mathematics

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer:

an angle supplementary to angle 3 is 125

Step-by-step explanation:

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Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

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Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

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The area of a circle is 161 in. What is the radius?

kirill [66]

Answer:

Approximately 7.16 in

Step-by-step explanation:

Hi there!

Area of a circle equation: $A=\pi r^2$ where r is the radius

Plug in the given area 161 in.²

$161=\pi r^2$

Divide both sides by π to isolate r²

$\frac{161}{\pi} =\frac{\pi r^2}{\pi} \\\frac{161}{\pi} =r^2$

Take the square root of both sides to isolate r

$=r^2\\\sqrt{\frac{161}{\pi}} =r\\7.16=r$

Therefore, the radius of the circle is approximately 7.16 in.

I hope this helps!

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3 years ago

4. If angle 2 = angle 3 and m angle 2= 55, find the measure of angle that is supplementary to angle 3.​

4. If angle 2 = angle 3 and m angle 2= 55, find the measure of angle that is supplementary to angle 3.