The bead is in a cylindrical shape and the formula for solving the volume of a cylinder is V=pi*r²*h where "r" is the radius, "h" for the height.
We have given values such as:
r=diameter/2 = 2/2 = 1mm
h= 8mm
Solving for the volume, we have:
V=3.14*1²*8
V=24.12 mm²
The third one would be the correct answer. I separately multiplied each number in the first section by each number in the second section. For instance, 0 x 2 is 0, 4 x 5 is 20, 5 x 3 is 15, and 2 x 0 is 0. All of these numbers are in the third answer.
Answer:
Step-by-step explanation:
https://d1avenlh0i1xmr.cloudfront.net/large/53ca8d0d-
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
