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galina1969 [7]
3 years ago
12

Hayden evaluated this expression using the order of operations, but he made a mistake. Which step includes Hayden's mistake?

Mathematics
1 answer:
Tems11 [23]3 years ago
7 0

9514 1404 393

Answer:

  step 3

Step-by-step explanation:

The multiplication indicated in step 2 should be carried out to get to step 3.

 = -6 +56 +9 . . . correct step 3

Then, step 4 is ...

  = 50 +9

and step 5 is ...

  = 59

Hayden's mistake is in step 3 where he ignores the order of operations requirement to perform multiplication before addition.

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Ali hops on his 3 wheeler and heads off at 12 mph. Two hours later, Fatimah chases after him on a moped at 18 mph. How far will
mash [69]

Answer: 72 miles.

Step-by-step explanation:

We know the relationship:

Distance = speed*time.

Then we can write the equation for distance as a function of time for Ali as:

A(t) = 12mph*t

where t is time in hours.

Fatimah's equation will be:

F(t) = 18mph*(t - 2h)

where the -2h appears because she starts two hours after Ali.

Fatimah will overtake Ali when F(t) = A(t) (their positions are the same)

Then we need to solve:

12mph*t = 18mph*(t - 2h)

12mph*t = 18mph*t - 18mph*2h

12mph*t = 18mph*t - 36 mi

36 mi = (18mph - 12mph)*t

36mi = 6mph*t

36mi/6mph = t

6h = t

So Ali travels for 6 hours before he gets overtaken, then the total distance that Ali travels is:

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3 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

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Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
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