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jeka94
3 years ago
9

Point b lies on segment AC. find the length of segment BC if AB = 4mm and AC = 4cm

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

Segment BC = 36 mm or 3.6 cm

Step by Step Explanation:

There are 10 mm in 1 cm

meaning that segment AC is 40 mm long

if AB is 4 mm and it is one part of the two, then we need to subtract that from the total to find out what is left.

40 - 4 = 36

Segment BC = 36 mm or 3.6 cm

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The sizes of the angles in degrees of the quadrilateral are
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5x+120

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Last year's computer models are discounted 20%. What was the original price to the nearest dollar of a computer that now costs $
Alisiya [41]

Answer:

<h3>$1850</h3>

Step-by-step explanation:

<h3>If the Original price was $ X , Then </h3>

x - 0.20x \:  = 1480

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x = 1480 \div 0.8

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2 years ago
Determine if (x+1) is a factor 4x^2 + 2x - 5Use synthetic division
ikadub [295]

Given

4x^2+2x-5

Divide it by (x+1) using synthetic division, as shown below

The green line is a minus sign.

Thus,

\Rightarrow4x^2+2x-5=(x+1)(4x-2)-3

Therefore, since the remainder is different than zero, (x+1) is not a factor of 4x^2+2x-5

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1 year ago
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The answer is 1 g
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1 year ago
Read 2 more answers
F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
10 months ago
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