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2 years ago

If an automobile travels at 40.0 m/s for 120.0 seconds, how far has the car traveled?

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

6 0

Answer:

Step-by-step explanation:

4800m

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There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45

4vir4ik [10]

I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
----------------------------
Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.

Neighborhood B
---------------------------
Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance.

3 0

2 years ago

A recipe for chocolate chip cookies with toffee bits and walnuts serves 8 people and needs 3 cups of flour. If Zachary wants to

tia_tia [17]

Answer:

Im pretty sure it's 5.25 cups of flour

Step-by-step explanation:

so we know that it takes 3 cups for 8 people and we don't know the amount for 14 people so write it as a fraction and cross multipy

For the equation

8/3=14/x

The cross product is

8*x=3*14

Solving for x

x=3×14/8

and reducing

x=5.25

5 0

3 years ago

Vivi scored 5 goals in Saskatoon sticks lacrosse tournament. This was 1/8 of her teams goals. How many goals did vivi’s team sco

yKpoI14uk [10]

5/ (1/8) = 40. Therefore the team scored 40 goals

7 0

3 years ago

How do you integrate arctan(x dx? i think that if you simplify the integral you get:?

Temka [501]

Integration by parts will help here. Letting $u=\arctan x$ and $\mathrm dv=\mathrm dx$ , you end up with $\mathrm du=\dfrac{\mathrm dx}{1+x^2}$ and $v=x$ . Now

$\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du$
$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx$

For the remaining integral, setting $y=1+x^2$ gives $\dfrac{\mathrm dy}2=x\,\mathrm dx$ , so

$\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C$

Putting everything together, you end up with

$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C$

6 0

3 years ago

16. (-4) = what is the answer<br>

kirill115 [55]

Answer

-64

just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64

5 0

2 years ago

Read 2 more answers