Answer:
The area of the Iris is 4 times greater.
Step-by-step explanation:
Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!
The average radius of the iris is 6mm, so we take this value.
Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

Therefore it's area
is:

When the iris contracts to 2mm, the radius of the pupil becomes:

Then it's area is
:

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

This is 4 times greater than the initial area.
The distance between the two endpoints is :
14.212 or about 14.21 ( rounded to the nearest hundredth)
Answer:
It's D.
Step-by-step explanation:
There are no repetitions of the x values in the ordered pairs so they are all functions.
"<span>5 to the negative 4th power over 5 to the 3rd</span>" translates to
5⁻⁴ / 5³
So you can just combine exponents.
5⁻⁴ / 5³ = 5⁻⁴ ⁻ ³ = 5⁻⁷ = 1/5⁷
Final answer: 1/5⁷
Answer:
-3,-6? im not sure what you're asking
Step-by-step explanation:
Using the coordinate plane, if you move 4 units to the left of 1 you get -3, moving it down 5 you get -6 then plug them in to the ordered pair (x,y) so (-3,-6)