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KiRa [710]
3 years ago
15

If f(x)=x-6/x, g(x)=x+4 and h(x)= 3x-2 (h*f*g)(x)

Mathematics
2 answers:
erastova [34]3 years ago
7 0

Answer:

Correct answer on ed is C.

Step-by-step explanation:

Just did the exam and it was correct.

Lelechka [254]3 years ago
5 0

Answer:

-14 + x\4 + x

Step-by-step explanation:

Start by plugging the g(x) function into the f(x) for every "x" you see, then take THAT answer and plug into the h(x) function for that "x" you see. You will arrive at the above answer.

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the standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. If x, y, and z eac
Studentka2010 [4]
For the units positions of all numbers we have:
z+7+5=4 \\ z+12=4
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
z+12=14 \\ z=2

For the tens positions of all numbers we have:
4+2+x+1=1 \\ 7+x=1
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
7+x=11 \\ x=4

Now we insert x and z to find out y:
42+27+45=y14 \\ 114=y14 \\ y=1

Now we need to find out the product of these three numbers:
x*y*z=4*1*2=8
3 0
3 years ago
Identify the slope and line intercept for y = 3x + 1<br> hs<br> The slope is:<br> The intercept is:
gogolik [260]

Answer:

The answerscan be calculated by doing the following steps;

Step-by-step explanation:

7 0
3 years ago
What is the slope of this line?<br> -1/5<br> 1/5<br> 5<br> -5
Tems11 [23]

Answer:

1/5

Step-by-step explanation:

The slope of a line at any given point is Rise/run

If I start at Point (0,2) and go to point (5,3)

I have to Rise 1 point up.

I go across, or run, 5.

1/5

8 0
3 years ago
The CEO of a corporation has $10,000 to give as bonuses. The amount of each employee receives depends on how many employees rece
STatiana [176]
Inversely proportional ...
5 0
3 years ago
Read 2 more answers
( 4x² - 5x + 1) + (-3x² + x +5)
Vesnalui [34]

Answer:

x^2-4x+6

Step-by-step explanation:

(4x^2 -5x +1) +(-3x^2 +x+5)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=4x^2-5x+1-3x^2+x+5\\\\\mathrm{Group\:like\:terms}\\=4x^2-3x^2-5x+x+1+5\\\\\mathrm{Add\:similar\:elements:}\:4x^2-3x^2=x^2\\=x^2-5x+x+1+5\\\\\mathrm{Add\:similar\:elements:}\:-5x+x=-4x\\=x^2-4x+1+5\\\\\mathrm{Add\:the\:numbers:}\:1+5=6\\=x^2-4x+6

4 0
3 years ago
Read 2 more answers
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