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2 years ago

A 4/7 inch pipe is to be shortened to 3/8 inch. How much must be removed?

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

6 0

11/56 inches or 0.196 inches must be removed.

The pipe measures 4/7 inches but needs to be reduced to 3/8 inches.

In order to find out the inches to be removed, you must subtract the length that the pipe should be from the length that it currently is.

<em>Length to be removed = 4/7 - 3/8</em>

You need a common denominator so find the lowest common factor of both denominators:

= 56

In the shared fraction, multiply the numerator by the number you get when you divide 56 by the denominator.

= 56/7 = 8 8 x 4 = 32

= 56 / 8 = 7 7 x 3 = 21

= (32 - 21) / 56

= 11 / 56 inches

= 0.196 inches

In conclusion, 11/56 inches must be removed to get the pipe to 3/8 inches

<em>Find out more at brainly.com/question/4681199.</em>

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