<span>X-2/y=2
</span><span>-2/y=2-x
</span><span>2/y=-2+x
</span><span>1/y=(-2+x)/2
</span>y=1/(<span>(-2+x)/2)
</span>y=2/<span>(-2+x)</span>
Midpoint of (x1,y1) and (x2,y2) is
so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is
the midpoint is (3.5,1)
The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).
<h3>What is a polar coordinate?</h3>
A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).
Next, we would determine the distance (r) and angle (θ) as follows:
r = √(3² + (-3)²)
r = √(9 + 9)
r = 3√2.
θ = tan⁻¹(-3/3)
θ = tan⁻¹(-1)
θ = 3π and 7π/4 (second and fourth quadrants).
Converting to degrees, we have:
θ = 135° and 315°.
Read more on polar coordinates here: brainly.com/question/3875211
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Complete Question:
Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°
: 88, 87, 89 90, 87, 85, 88, 91, 86, 86, 88, 89<br>what's is the inerquartile range
andreyandreev [35.5K]
I think 88 i don’t really know
Answer: -5x= -11
Step-by-step explanation:
