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BabaBlast [244]
3 years ago
12

A sports drink recipe calls for table spoons of powdered drink mix and 12 ounces of water to make two 4/3 batches. How many batc

hes of sports drink can you make with 5 tablespoons of powdered drink mix and 42 ounces of water?
Mathematics
2 answers:
KIM [24]3 years ago
8 0

Answer:8.4

explanation:

it just is the answer

Cloud [144]3 years ago
7 0

Answer: 8.4

Step-by-step explanation:

Hope it helps!

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The ratio of boys to girls in a class is 2:5, what fraction of the class are boys?
Andre45 [30]

Step-by-step explanation:

= \frac{2}{2 + 5}  \\  =  \frac{2}{7}

HOPE THIS HELPS!

7 0
1 year ago
Question is on the screenshot
vesna_86 [32]
Answer: V= 150π

V= πr^2 h
V= π(5)^2 (6)
V= 150π
3 0
3 years ago
Read 2 more answers
You can’t decide which estate agent to use to sell your home, so you research the number of properties each estate agent has sol
Triss [41]

Answer:

B. 130 70

Step-by-step explanation:

Agent B sold the highest number (53.85% ) of houses given the number of listed houses.

Find the percentage of houses each agent sold.

For A

x/100 * 150 = 75

cross multiply and find x, that would be 50%

For B

x/100 * 130 = 70

cross multiply and find x, that would be 53.85%

for C

x/100 *145 = 75

cross multiply and find x, that would be 51.72%

7 0
3 years ago
Which operation should go in the blue spot to make this equation true?
Rasek [7]

Answer:

for the first one is <em><u>Addition</u></em><em><u>. </u></em> the second one is

7 0
3 years ago
Can someone please help me with this problem ASAP thank you
Step2247 [10]

3-degree polynomial is f(x )= [x^{3 }-\frac{9}{7} x^{2}+9x-\frac{81}{7} ]

Step-by-step explanation:

Given that polynomial f(x) is 3-degree polynomial and Zeros/Roots at x= \frac{9}{7} and x= -3i

In order to find the equation of a 3-degree polynomial, we need 3 roots.

Here, One of Root is real number x=\frac{9}{7} and another root is an imaginary number x=(-3i)

It is necessary to note that imaginary roots always come in pair of conjugates

Therefore, Comjugate0 of x =(-3i) is 3rd root

Conjugate of (-3i) is 3i

Evaluting equation of polynomial,

=[x-3i][x+3i][x-\frac{9}{7} ]

=[x^{2}-(3i)^{2}][x-\frac{9}{7} ]

=[x^{2}-(9)(i)^{2}][x-\frac{9}{7} ]

=[x^{2}+9][x-\frac{9}{7} ]

f(x )= [x^{3 }-\frac{9}{7} x^{2}+9x-\frac{81}{7} ]

6 0
3 years ago
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