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Lady_Fox [76]
3 years ago
9

Write sin 29 degrees 32 minutes in terms of it cofunction

Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer:

Sin 29° 32' = Cos 60° 28'

Step-by-step explanation:

Here in this problem, we have to write Sin 29° 32' in terms of its co-function.

We know that co-function of Sin Ф = Cos ( 90° - Ф ).

Therefore, we have to find a complementary angle of 29° 32'.

So, ( 90° - 29° 32' ) = 60° 28'

Therefore, Sin 29° 32' = Cos 60° 28' ( Answer )

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A line passes through the point -10,9 and has a slope of 1/2. Write an equation in slope-intercept form for this line
vitfil [10]

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

y = (1/2)x + b

We want a value of b such that it forces the line to go through point (-10,9).  Enter that point in the equation and solve for b:

y = (1/2)x + b

9 = (1/2)*(-10) + b

9 = -5 + b

b = 14

The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

y = (1/2)x + 14

See attachment.

7 0
2 years ago
Find the measures of the complementary angles that satisfy each case.
telo118 [61]

Answer:

first - 25 degrees, second - 65 degrees

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the volume of a sphere with a radius of 5 meters rounded to the nearest square meter.
-BARSIC- [3]

Step-by-step explanation:

V = 4/3 π r³

V = 4/3 π (5 m)³

V = 524 m³

8 0
3 years ago
Use a spinner to find the theoretical probability of spinning an even number. What is the theoretical probability of spinning an
stiv31 [10]

Answer:

4/8

Step-by-step explanation:

There are half even and half odd numbers on a spinner so it is 1/2 of 8 which is 4. Then you put the 4 over 8 to gain your probability.

7 0
3 years ago
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Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the
s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

F(x)=\sqrt{x-2}

G(x)=(x-2)^2

H(x)=x^2+2

We compose F(x) and G(x) to get:

(F\circ G)(x)=F(G(x))

(F\circ G)(x)=F((x-2)^2)

(F\circ G)(x)=\sqrt{(x-2)^2-2}

(F\circ G)(x)=\sqrt{x^2-4x+4-2}

(F\circ G)(x)=\sqrt{x^2-4x+2}

(F\circ G)(x)\ne x

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

(F\circ H)(x)=F(H(x))

(F\circ H)(x)=F(x^2+2)

(F\circ H)(x)=\sqrt{x^2+2-2}

We simplify to get:

(F\circ H)(x)=\sqrt{x^2}

(F\circ H)(x)=x

Since (F\circ H)(x)=x, H(x) is an inverse of F(x)

3 0
3 years ago
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