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3 years ago

Write sin 29 degrees 32 minutes in terms of it cofunction

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Answer:

Sin 29° 32' = Cos 60° 28'

Step-by-step explanation:

Here in this problem, we have to write Sin 29° 32' in terms of its co-function.

We know that co-function of Sin Ф = Cos ( 90° - Ф ).

Therefore, we have to find a complementary angle of 29° 32'.

So, ( 90° - 29° 32' ) = 60° 28'

Therefore, Sin 29° 32' = Cos 60° 28' ( Answer )

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Given the system of equations:

Studentka2010 [4]

Answer:

X=-11

Y=8

Final: (-11,8)

Step-by-step explanation:

Isolate the Y variable

3x = -1 - 4y

3x - 1 = -4y

divide by -4

y = -3/4x - 1/4

Next equation, do the same thing

2x + 3y = 14

3y = 14 - 2x

divide by 3

y = 4 2/3 - 2/3x

Set the two equations (that are set equal to Y) equal to each other

-3/4x - 1/4 = 4 2/3 - 2/3x

+ 1/4 + 1/4

-3/4x = 11/12 - 2/3x

+2/3x +2/3x

-1/12x = 11/12

Now divide both sides by -1/12

x = -11

(11/12 was found by finding the LCM(Least Common Multiple) of 3 and 4, which is 12 and getting the equivalent factor for the denominator of 12. Same went for the -1/12)

Plug -11 in for x for one of the previous equations

3(-11) = -1 - 4y

-33 = -1 - 4y

+1 +1

-32 = -4y

Divide both sides by -4

y = 8

(-11,8)

6 0

3 years ago

Read 2 more answers

Marc y uses 1 bottle of blue paint, 2 bottles of yellow paint, and 1 bottle of red paint for one painting. how many bottles will

Tresset [83]

she will need 4 bottles

3 0

4 years ago

Read 2 more answers

What is the completely factored form of f(x)=x3−7x2+2x+4?

sladkih [1.3K]

Answer:

The Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

Step-by-step explanation:

Given;

$f(x)=x^{3} -7\times x^{2} +2x+4$

To solve for x we factorize the right side of

$f(x)=x^{3} -7\times x^{2} +2x+4$

Let Substitute x for various values to check whether remainder is zero.

$f(1)=1^{3} -7\times 1^{2} +2\times 1+4$

Hence $x-1$ is a factor of the function.

Do synthetic division to find the quotient

$1$ $1$ $-7$ $2$ $4$

$1$ $-6$ $-4$

_____________________

$1$ $-6$ $-4$ $0$

We get remainder 0 and quotient as,

$x^{2} -(6\times x)-4$

By using Quadratic Formula;

$x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

Plug 'a' , 'b' and 'c' value from $x^{2} -(6\times x)-4$ equation,

$x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}$

$x=\frac{6\pm\sqrt{36+16 } }{2}$

$x=\frac{6\pm\sqrt{52} }{2}$

$x=3+\sqrt{13}$ and $x=3-\sqrt{13}$

The values of 'x' are $1$ , $3+\sqrt{13}$ and $3-\sqrt{13}$

So the Factored form is

$f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )$

7 0

3 years ago

Find the value of X.

Mkey [24]

Answer:

hai

like you see, there are 2 line on the triangle.

68° is looking in front of one line, so the other line's front have to be 68°

now we found 2 corner of triangle.

a triangle's sum of interior angles equal to 180°

68°+68° = 136°.

now i have to remove 136 from 180 to find our x

180°-136° = 44°

x = 44°

good luck(:

3 0

3 years ago

Can someone help me with this graph goes down to -10

Lilit [14]

Answer:

(5,7)

Step-by-step explanation:

x + 2 = 2x - 3

2x - x = 5

x = 5

When X = 5, Y= 7

Best regards

6 0

3 years ago