All categories

3 years ago

Write sin 29 degrees 32 minutes in terms of it cofunction

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Answer:

Sin 29° 32' = Cos 60° 28'

Step-by-step explanation:

Here in this problem, we have to write Sin 29° 32' in terms of its co-function.

We know that co-function of Sin Ф = Cos ( 90° - Ф ).

Therefore, we have to find a complementary angle of 29° 32'.

So, ( 90° - 29° 32' ) = 60° 28'

Therefore, Sin 29° 32' = Cos 60° 28' ( Answer )

You might be interested in

A line passes through the point -10,9 and has a slope of 1/2. Write an equation in slope-intercept form for this line

vitfil [10]

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

y = (1/2)x + b

We want a value of b such that it forces the line to go through point (-10,9). Enter that point in the equation and solve for b:

y = (1/2)x + b

9 = (1/2)*(-10) + b

9 = -5 + b

b = 14

The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

y = (1/2)x + 14

See attachment.

7 0

2 years ago

Find the measures of the complementary angles that satisfy each case.

telo118 [61]

Answer:

first - 25 degrees, second - 65 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the volume of a sphere with a radius of 5 meters rounded to the nearest square meter.

-BARSIC- [3]

Step-by-step explanation:

V = 4/3 π r³

V = 4/3 π (5 m)³

V = 524 m³

8 0

3 years ago

Use a spinner to find the theoretical probability of spinning an even number. What is the theoretical probability of spinning an

stiv31 [10]

Answer:

4/8

Step-by-step explanation:

There are half even and half odd numbers on a spinner so it is 1/2 of 8 which is 4. Then you put the 4 over 8 to gain your probability.

7 0

3 years ago

Read 2 more answers

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

3 years ago