Answer: w=5 , L= 2+2(5)=12
Step-by-step explanation:
L=2+2W
A= 60
LxW=60, now we will replace the L
(2+2W)(W)=60 we multiply
2w^2+2w=60
2w^2+2w-60=0 we divide by 2 the equation so we can work easier
w^2+w-30=0
find out w using the quadratic equation
we will get 2 solution,
w=5 and another solution is -6, which is not valid, as the side can not be negative
Should be 1/4 to my knowledge.
Answer:
Part A
W W W M W W T W W L W W
W W M M W M T W M L W M
W W T M W T T W T L W T
W W L M W L T W L L W L
W M W M M W T M W L M W
W M M M M M T M M L M M
W M T M M T T M T L M T
W M L M M L T M L L M L
W T W M T W T T W L T W
W T M M T M T T M L T M
W T T M T T T T T L T T
W T L M T L T T L L T L
W L W M L W T L W L L W
W L M M L M T L M L L M
W L T M L T T L T L L T
W L L M L L T L L L L L
Part B
There are 64 possible outcomes. The sample size is 64.
Part C
To find the probability that Erin drinks lemonade one day, tea one day, and water one day, consider all the cases in which L, T, and W occur one time. Because the order doesn't matter in this scenario, these six outcomes from the list represent the desired event: W T L, T W L, T L W, W L T, L W T, and L T W.
The size of the sample space is 64. So, the probability that Erin drinks lemonade one day, tea one day, and water one day is 3/32.
Part D
To find the probability that Erin drinks water on two days and lemonade one day, we consider all the cases in which two Ws and one L occur. Because the order doesn't matter in this scenario, these three outcomes from the list represent the event: W W L, W L W, and L W W.
The size of the sample space is 64. So, the probability that Erin drinks water two days and lemonade one day is 3/64
Step-by-step explanation:
Answer:
y=1
x=-5
Step-by-step explanation:
3x+y=-14
4x+4y=-16
y=-3x-14
4x+4y=-16
y=-3x-14
4(-3x-14)+4x=-16
y=-3x-14
-8x-56=-16
y=-3x-14
-8x=40
y=-3x-14
x=-5
y=1
x=-5
