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Sergeeva-Olga [200]
3 years ago
14

Two trains leave towns 912 kilometers apart at the same time and travel toward each other. One train travels 12

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

Step-by-step explanation:

Remark

The two trains are travelling towards each other. That means that their total distance = 912 km. Neither one has gone that distance by itself. The effect this has on the question is that you add the two rates multiplied by time.

Givens

r1 = x

r2 = x + 12

t = 3 hours

d = 912 km

Equation

d = r * t

r1 * t + r2 * t = 912

Solution

3x    + 3*(x + 12) = 912          Remove the brackets

3x +  3x + 36 = 912              Combine like terms

6x + 36 =   912                     Subtract 36 from both sides

 <u>     -36      -36</u>

6x       =      876                   Divide both sides by 6  

6x/6   =       876/6

x =               146 km/h

Answer

Slow train = 146 km/hr

Fast train = 146 + 12 = 158 km/hr

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A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:
Dima020 [189]

Answer:

Part A) y=\frac{3}{4}x-\frac{1}{4}  

Part B)  y=\frac{2}{7}x-\frac{5}{7}

Part C) y=\frac{2}{7}x+\frac{8}{7}

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the  median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

N(3, 2) and M(-1,-1)

substitute the values

m=\frac{-1-2}{-1-3}

m=\frac{-3}{-4}

m=\frac{3}{4}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{3}{4}

point\ N(3, 2)

substitute

y-2=\frac{3}{4}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{3}{4}x-\frac{9}{4}

y=\frac{3}{4}x-\frac{9}{4}+2

y=\frac{3}{4}x-\frac{1}{4}  

Part B) Find the equation of the  right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 4

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ M(-1,-1) ----> midpoint LP

substitute

y+1=\frac{2}{7}(x+1)

step 5

Convert to slope intercept form

Isolate the variable y

y+1=\frac{2}{7}x+\frac{2}{7}

y=\frac{2}{7}x+\frac{2}{7}-1

y=\frac{2}{7}x-\frac{5}{7}

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ N(3,2)

substitute

y-2=\frac{2}{7}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{2}{7}x-\frac{6}{7}

y=\frac{2}{7}x-\frac{6}{7}+2

y=\frac{2}{7}x+\frac{8}{7}

7 0
3 years ago
A bag of marbles has 6 red marbles and 7 green marbles in it. What is the percent probability of pulling a green marble out of t
soldi70 [24.7K]

Answer:

If a bag contains 4 red marbles, 3 blue marbles, and 7 green marbles and a marble is randomly selected from the bag, what is the probability that it is blue? P=3/(3+4+7)=3/14 because each of 14 marbles is equally likely to be drawn.

Step-by-step explanation:

7 0
3 years ago
The mean of 10 values is 19. If further 5 values are
Leokris [45]

Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is  a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300                since 15(20)=300

Now let's look at the first 10:  We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190                               since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

      k+l+m+n+o=300-190

      k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0
3 years ago
The answer ............
suter [353]

Answer:

f^-1(x) = ( x + 6 )/4

Step-by-step explanation:

f(x) is the same as...y = 4x + 6....and then try to make x the subject of formula

y + 6 = 4x

x = (y + 6)/4....then when writing f^-1(x)...replace y with x

f^-1(x) = ( x + 6 )/4

3 0
3 years ago
Which expression is equivalent to 6 - (-2)?<br> -6 + 2<br> -6 - 2<br> 6+2<br> 6-2
Sveta_85 [38]

Answer:

6+2

Step-by-step explanation:

6 - ( - 2)

Distribute the negative in.

<u>Negative</u><u> </u><u>Multiply</u><u> </u><u>Negative</u><u> </u><u>must</u><u> </u><u>equal</u><u> </u><u>Positive</u><u>.</u>

6 + 2

7 0
3 years ago
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