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nevsk [136]
3 years ago
7

3(x-1) - 8 = 4(1+x) +5. Too hard, i keep getting confused

Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

3(x-1)-8=4(1+x)+5  

One solution was found :

                  x = -20

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    3*(x-1)-8-(4*(1+x)+5)=0  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((3•(x-1))-8)-(4•(x+1)+5)  = 0  

Step  2  :

Equation at the end of step  2  :

 (3 • (x - 1) -  8) -  (4x + 9)  = 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  -x - 20  =   -1 • (x + 20)  

Equation at the end of step  4  :

 -x - 20  = 0  

Step  5  :

Solving a Single Variable Equation :

5.1      Solve  :    -x-20 = 0  

Add  20  to both sides of the equation :  

                     -x = 20

Multiply both sides of the equation by (-1) :  x = -20

One solution was found :

                  x = -20

hope this is wht u wanted

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A youth basketball coach has 12 kids on his team and he selects 5 kids to start each game. To be fair he wants to start a differ
alisha [4.7K]

_{12}C_5=\dfrac{12!}{5!7!}=\dfrac{8\cdot9\cdot10\cdot11\cdot12}{120}=792

792>20, so yeah, he will be able.

8 0
3 years ago
What is the slope of a line that contains the points (-1, 9) And 5, 21)
TEA [102]

C.) 2

21-9= 12

5--1= 6

12/6+= 2


8 0
3 years ago
HELP ASAP !! i’ll give you the brainliest answer as long it’s correct plsss helpp
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Answer:

its b, and why does everyone want brainllest

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However,
horsena [70]

Answer:

The mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

Step-by-step explanation:

We are given that records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.

On a typical​ Saturday, the​ oil-change facility will perform 35 oil changes between 10 A.M. and 12 P.M. Assuming that data follows normal distribution.

Let \bar X = <u><em>sample mean time</em></u>

The z score probability distribution for sample mean is given by;

                          Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 16.2 minutes

            \sigma = standard deviation = 3.4 minutes

            n = sample size = 35 oil changes

<u>Now, the mean oil-change time that would there be a 10% chance of being at or below is given by;</u>

<u></u>

          P(X \leq x) = 0.10          {where x is required mean oil-change time}

          P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

          P(Z \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

Now, in the z table the critical value of X which represents the below 10% of the probability area is given as -1.282, that means;

                  \frac{x-16.2}{\frac{3.4}{\sqrt{35} } }  =  -1.282

               x - 16.2  =  -1.282 \times {\frac{3.4}{\sqrt{35} } }

                         x  =  16.2 - 0.74 = <u>15.46 minutes</u>

Hence, the mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

8 0
3 years ago
convert this rational number into a decimal form:3/7,round to the nearest thousandth,NEED HELP ASAP!!
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.429 I think is the correct answer, I'm not 100% cure though.
 
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