Is their an image to go along with this question ?
Answer:
6.0520
Step-by-step explanation:
Given that:
Mean = 5.85
Standard deviation = 0.24
Let N denote the 80th percentile.
P(X < N) = 0.8
Using the Excel formula: = NORM.INV(0.8,5.85,0.24)
The 80th percentile for the diameters of mandarin oranges:
= 6.0520 (to 4 decimal place)
Answer:
P ≈ 100
Step-by-step explanation:
260 = P(1+0.054/365)^365(14)
260 = P(1.000147945)^5110
260= P(2.129621112)
P= 122.087444818
P ≈ 100