So, what we need to do is find out the chance you will pull an M or an L out of the scrabble bag on your next turn.
Our first step is finding out how many pieces total are in the bag. This will become the denominator in our answer. To do this, we just need to add up all the pieces we know are in the bag! From the question, we know there are <span>5 As, 3 Es, 1 Z, 2 Ms, 3 Ls, and 1 <span>Y left in the bag. So 5 + 3 + 1 + 2 + 3 +1 should give us 15 total pieces to pick from.
Next, we need to know the total of Ls and Ms left in the bag that we want to pick. This number will be the numerator in our answer. From the question, we know there are 2 Ms and 3 Ls in the bag. Because 2+3 = 5, that means out final fraction for this problem should be 5/15!
Unfortunately, that is not an actual answer for the question, so that means we have to simplify by finding the biggest number that goes into both the top and bottom of our fraction. To get 5, we can only use the numbers 1 and 5. To get 15, we can use 1, 3, 5, and 15. From this, it looks like both the top and the bottom are divisible by 5. When we divide the top by 5 we end up with a 1, and when we divide the bottom by 5 we end up with a 3, meaning our final fraction is D) 1/3!</span></span>
B I’m guessing, never really worked with something like this before though
So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.
So for now we can simply calculate that we have spent around 100$ which means 20 boxes. The remaining money left is 77$ so we can buy 77/3.5 = 22 only 22 boxes with that money. Hence a total of 42 boxes.
Answer:
2403.2
Step-by-step explanation:
We get the length of the hypotenuse, and the base angle. To find the length of the base, we use the cosine of 16° since it is equal to the adjacent side length/ hypotenuse side length or cos 16°= x/2500. The isolate x by multiplying both sides by 2500. The cos 16° is around 0.96126, multiplied by 2500 (cos 16°(2500)) = 2403.1