Answer:
2 is the number because half of 5 is 2.5
<span>3down votefavorite1Find minimum and maximum value of function <span>f(x,y)=3x+4y+|x−y|</span> on circle<span>{(x,y):<span>x2</span>+<span>y2</span>=1}</span>I used polar coordinate system. So I have <span>x=cost</span> and <span>y=sint</span> where <span>t∈[0,2π)</span>.Then i exploited definition of absolute function and i got:<span>h(t)=<span>{<span><span>4cost+3sintt∈[0,<span>π4</span>]∪[<span>54</span>π,2π)</span><span>2cost+5sintt∈(<span>π4</span>,<span>54</span>π)</span></span></span></span>Hence i received following critical points (earlier i computed first derivative):<span>cost=±<span>45</span>∨cost=±<span>2<span>√29</span></span></span>Then i computed second derivative and after all i received that in <span>(<span>2<span>√29</span></span>,<span>5<span>√29</span></span>)</span> is maximum equal <span>√29</span> and in <span>(−<span>45</span>,−<span>35</span>)</span> is minimum equal <span>−<span>235</span></span><span>
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Answer: 15
Step-by-step explanation:
x:9 = 25:15
x = 25:15*9 = 15
10/1 = 43.5/x
cross multiply
10x=43.5
divide by 10 on each side
x = 4.35
it will take 4.35 minutes
In this case we have the following trinomial:

By definition, the factorization is a technique that consists in the mathematical decomposition of an expression, in the form of a product. Having said that, we can factor the given trinomial in the following way:
We look for two numbers that when multiplied give as result 42, and when summed give as result -13.
The numbers that meet these two conditions are -6 and -7 by:

So, we have:

Answer:
The binomials associated with the given trinomial are
and
.