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3 years ago

Name the place value of highlighted digit 35.052

Mathematics

2 answers:

Lelechka [254]3 years ago

5 0

The your answer will be the hundredths place

DanielleElmas [232]3 years ago

3 0

The highlighted 5 in 35.052 is in the hundredths place.

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Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How

marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25$

And rounded up we have that n=601

3 0

3 years ago

CAN SOMEONE PLEASE HELP ME??

adell [148]

Answer:

1. 1.632*10^7

2. 6.6248*10^-3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

You want to rent a television. Company A charges $25 per week plus a one-time fee of $52. Company B charges $37 per week plus a

RUDIKE [14]

52+25=77+25=102+25=127
16+36=53+37=90+37=127
Answer 3 weeks

8 0

3 years ago

3. Martin's car had 86,456 miles on it. Of that distance, Martin's wife drove 24,901

Jet001 [13]

Answer:

Martin Drove about 60,000

Martin Drove exactly 53,558

Step-by-step explanation:

90,000 - (20,000 +10,000) = x

60,000 = x

86,456 - (24,901 - 7,997) = x

53,558 = x

8 0

3 years ago

involving the selection of two apples from a bag of red and yellow apples without replacement. Assume that the bag has a total o

ivolga24 [154]

Answer:

1) The probability that the second apple is red is 0.7143 (71.43%).

2) The probability that at least one red apple is picked 0.9341 (93.41%).

Step-by-step explanation:

We can make a probability tree as the attached picture.

1) There are 2 ways in the probability tree when the second apple is red:

Both apples are red:

P(R∩R)= $\frac{10}{14}\frac{9}{13}$ =0.4945

Only the second apple is red:

P(Y∩R)= $\frac{4}{14}\frac{10}{13}$ =0.2198

The probability that the second apple is red is the sum of the previous probabilities.

P(2nd R)=P(R∩R)+P(Y∩R)=0.4945+0.2198=0.7143

2) To find the probability that at least one apple is red, we can get the probability of none of the apples is red and then it will be subtracted from 1.

The way in the probability tree is Y∩Y:

P(Y∩Y)= $\frac{4}{14} \frac{3}{13}$ =0.0659

P(at least 1 R)= 1-P(Y∩Y)=1-0.0659=0.9341

8 0

3 years ago

Read 2 more answers