Question

Solve by completing the square. x2-6x+8 Show solving steps please.

Answer 1

Answer:

x = 2 , x = 4

Step-by-step explanation:

To solve the expression equate it to zero

x² - 6x + 8 = 0 ( subtract 8 from both sides )

x² - 6x = - 8

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = - 8 + 9

(x - 3)² = 1 ( take square root of both sides )

x - 3 = ± $\sqrt{1}$ = ± 1 ( add 3 to both sides )

x = 3 ± 1

Then

x = 3 - 1 = 2 or x = 3 + 1 = 4

Answer 2

Answer:

(x−2)(x−4)

Step-by-step explanation:

Let's factor x2−6x+8

x2−6x+8

The middle number is -6 and the last number is 8.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -6

Multiply together to get 8

Can you think of the two numbers?

Try -2 and -4:

-2+-4 = -6

-2*-4 = 8

Fill in the blanks in

(x+_)(x+_)

with -2 and -4 to get...

(x-2)(x-4)

Hope this helps! Also, if it's no trouble, can I have brainliest? Thanks! :D