Please someone help me solve this.
1 answer:
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Answer:
The equation of the line containing (4,2) and (3,5) in the slope-intercept form will be:
- y=-3x+14
Step-by-step explanation:
Given the points
- (4, 2)
- (3, 5)
We know that the slope-intercept form of the line equation is
where m is the slope and b is the y-intercept
substituting m=-3 and the point (4, 2) to get the y-intercept i.e. b
2=(-3)4 + b
2 = -12 + b
b = 2+12
b = 14
Now, substituting b=14 and m=-3 in the slope-intercept form to determine the equation of a line in the slope-intercept.
y=(-3)x+(14)
y=-3x+14
Thus, the equation of the line containing (4,2) and (3,5) in the slope-intercept form will be:
- y=-3x+14
Answer:
p =
Step-by-step explanation:
q=- r÷ t using BODMAS
q = - (r/t)
q + r/t =
p=