All categories

3 years ago

Hi help with these please and thank yu? :)

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

the first one is A

b/c when you calculate it comes 0 = 6

And the second one is D

b/c when you calculate it comes 0 = 2

if it's helpful ❤❤❤

THANK YOU.

You might be interested in

I can't figure out the answer

Rudik [331]

3 should be the answer

4 0

3 years ago

Read 2 more answers

Which The following radical functions is graphed below

maks197457 [2]

Answer:

Option A

Step-by-step explanation:

From the graph attached,

Vertical asymptote of the given function → x = -4

Horizontal asymptote → y = 0

Oblique asymptote → None

Therefore, graph that has been given in the picture is,

F(x) = $\frac{1}{(x+4)^2}$

Option (A) will be the answer.

5 0

3 years ago

8 pencils for 14 dollars

Schach [20]

Answer:

1 pencil will be for 1.75 $

4 0

2 years ago

Read 2 more answers

Assume that women's heights are normally distributed with a mean given by mu equals 62.3 in, and a standard deviation given by

Salsk061 [2.6K]

Answer: a) 0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean : $\mu= 62.3\text{ in}$

Standard deviation : $\sigma = \text{2.4 in}$

The formula for z -score :

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

a) Sample size = 1

For x= 63 in. ,

$z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29$

The p-value = $P(z$

$0.6140918\approx0.6141$

Thus, the probability is approximately = 0.6141

b) Sample size = 47

For x= 63 ,

$z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0$

The p-value = $P(z$

$=0.9772498\approx0.9772$

Thus , the probability that they have a mean height less than 63 in =0.9772.

8 0

3 years ago

Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

oksano4ka [1.4K]

Answer:

1/q^30 (startfraction 1 over q subscript 30 baseline end fraction)

Step-by-step explanation:

just took quiz

5 0

3 years ago

Read 2 more answers