Question

Just need the equation

Answer 1

$a. x = -2\\b. x = \frac{3}{2} \\c. x = 0\\d. x = -\frac{1}{5}$

Each of the equations can be solved as shown below:

a. $3x + 7 = - x - 1$

$3x + 7 + x = - x - 1 + x$ (addition property of equality)

$4x + 7 = - 1\\4x + 7 - 7 = -1-7$ (Subtraction property of equality)

$4x = -8\\\frac{4x}{4} = \frac{-8}{4}$ (Division property of equality)

$x = -2$

b. $1 - 2x + 5 = 4x - 3$

Add like terms

$6 - 2x = 4x - 3\\\\6 - 2x - 6 = 4x - 3 - 6$ (Subtraction property of equality)

$- 2x = 4x - 9\\-2x - 4x = 4x -9 - 4x$ (Subtraction property of equality)

$-6x = -9 \\\frac{-6x}{-6} = \frac{-9}{-6}$ (Division property of equality)

$x = \frac{3}{2}$

c. $4x - 2 + x =-2 + 2x$

$5x - 2 = -2 + 2x\\5x - 2x = -2 + 2\\3x = 0\\ x = \frac{0}{3} \\x = 0$

d. $3x - 4 + 1 = - 2x -5 + 5x$

$3x - 3 = - 7x -5\\3x + 7x = 3 - 5\\10x = -2\\x = \frac{-2}{10} \\x = -\frac{1}{5}$

The value of x in each equation are:

$a. x = -2\\b. x = \frac{3}{2} \\c. x = 0\\d. x = -\frac{1}{5}$

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