All categories

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

never [62]3 years ago

7 0

B) It cost Ralph 15 dollars to drive 210 miles in 2008.

You might be interested in

Find the two square roots of each complex number by creating and solving polynomial equations.

son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3 + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

$\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))$

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad

w₁= $\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))$ =4-i

w₂= $\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))$ =-1+i

2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad

w₁= $\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))$ = 3 - i

w₂= $\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))$ = -3 + i

3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad

w₁= $\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))$ = 1 + 2i

w₂= $\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))$ = -1 - 2i

4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad

w₁= $\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))$ = 2- 3i

w₂= $\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))$ = -2 + 3i

5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad

w₁= $\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))$ = 5 - 2i

w₂= $\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))$ = -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁= $\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))$ = 5 - 3i

w₂= $\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))$ = -5 + 3i

6 0

3 years ago

sets of linear systems wherein there is one Consistent & Dependent, Consistent & Independent, and one Inconsistent.

Mamont248 [21]

Answer:

What is the difference between entering a formula and entering data ??

3 0

2 years ago

In a metal fabrication process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n

Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, $\bar{x}$ = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314$

$14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)$

is the required confidence interval for the true mean length of rods.

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=A%28x%29%3D3%5E2" id="TexFormula1" title="A(x)=3^2" alt="A(x)=3^2" align="absmiddle" class="la

kogti [31]

It is good equation. Look, that:
81 = 3 x 3 x 3 x 3 = 3^4.
So you have to solve:
3^x = 3^4
exponents have to be the same, so
x=4
That's mean that A(4) = 81

5 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEEEEEE

Nataliya [291]

Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5 therefore x = 7

a) let the number be x

therefore if $\frac{3}{2} x + \frac{9}{4} = \frac{51}{4} \Rightarrow 1.5x + 2.25 = 12.75$ then the number x = 7.

This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

quarters, the number is x = 5,

$\frac{9}{4} x + \frac{3}{2} = \frac{51}{4} \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 5.

$2.25x + 1.5 = 12.75 \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

3 0

3 years ago