Answer:
D
Step-by-step explanation:
But basically, one by one you try moving the terms out of the radical.
75 is also 25 * 3 and since 25 has a perfect square root of 5 that goes out and 3 stays inside the radical.
x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.
y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.
Finally, z is just z it can't be taken out so it stays inside the radical.
Hope that helps!
<u>For the whole numbers:</u>
24
26
23
25
21
46
63
57
75
91
Answer:
Following are the solution to the given equation:
Step-by-step explanation:
Please find the complete question in the attachment file.
In point a:




In point b:


In point c:


In point d:



Te x intercepts are where the graph crosses the x axis or wher y=0
the y intercept is where the graph crosses the y axis or where x=0
to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a
so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8
vertex is (-2,-8)
intercepts
x intercept is where y=0
0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)
yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)
vertex at (-2,-8)
xints at x=

and

or at the points

and

yint at y=7 or at (7,0)