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Allushta [10]
3 years ago
5

What does point 4, 32 mean in this situation

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0
Everyone one this app with the username that starts with bean and have random numbers are annoying and scammers they are on my acc too also you need to show the “situation” for someone to answer try sharing a picture
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Greatest common factor of 24,40,56
Tema [17]
8 is the greatest common factor

8 0
3 years ago
Read 2 more answers
in addition to dog walking on Tuesday Eric made $45 dog sitting at one of his customers homes if he made $168 on Tuesday right i
Rus_ich [418]

Since we don't know how much Eric makes per dog, let's let <em>x </em>represent that value. Let's also let <em>y</em> represent our answer.

First, let's consider the two numbers we KNOW will be in the equation. The 56 that Eric made dog sitting and the 168 he made in total on Tuesday. Now, we're going to need to use subtraction and division in this equation.

(168 - 45) ÷ <em>x</em> = <em>y</em>


Hope this answer helped you out. :)

8 0
3 years ago
The total cost of a jacket and a pair of shoes was $52.95. If the price of the jacket was $3.87 less than the pair of shoes, wha
abruzzese [7]

The price of jacket was $24.54

Step-by-step explanation:

Let,

Cost of jacket = x

Cost of pair of shoes = y

According to given statement;

x+y=52.95   Eqn 1

x = y-3.87    Eqn 2

Putting value of x from Eqn 2 in Eqn 1

(y-3.87)+y=52.95\\y-3.87+y=52.95\\2y=52.95+3.87\\2y=56.82\\

Dividing both sides by 2

\frac{2y}{2}=\frac{56.82}{2}\\y=28.41

Putting y=28.41 in Eqn 2,

x=28.41-3.87\\x=24.54

The price of jacket was $24.54

Keywords: linear equation, division

Learn more about linear equations at:

  • brainly.com/question/2666836
  • brainly.com/question/2678748

#LearnwithBrainly

8 0
3 years ago
2. Consider the following graph of a quadratic function.
Stella [2.4K]

Answer:

see the procedure

Step-by-step explanation:

Looking at the graph we have

The graph represent a  vertical parabola open upward

The vertex is a minimum

The vertex is the point (-4,-3)

The domain is the interval -----> (-∞,∞)

The Domain is all real numbers

The range is the interval ----> [-3,∞)

y\geq -3

The range is all real numbers greater than or equal to -3

The graph is increasing in the interval (-4,∞)

The graph is decreasing in the interval (-∞,-4)

The minimum of the graph is y=-3 occurs at x=-4

5 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
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