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exis [7]
2 years ago
5

A graph of a system of two linear equations is shown. Write the system of linear equations represented by the graph

Mathematics
1 answer:
DiKsa [7]2 years ago
8 0
Line1: y = -x + 2
Line2: y = 2x - 1

Solution: (1,1)
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When The sum of 1. 3240 and 1. 4872 is subtracted from 4. 0121 it will give you the difference of
Paladinen [302]

Answer:

C. 1.2009

Step-by-step explanation:

1.3240 + 1.4872 = 2.8112

4.0121 - 2.8112 = 1.2009 - C

8 0
3 years ago
What is the answer to y=2x+3<br> and y=3x+5
Alla [95]

Answer:

(-2,-1)

Step-by-step explanation:

y=2x+3

y=3x+5

so y=y

then:

2x+3=3x+5

3-5= 3x-2x

-2= X

x=-2

3 0
3 years ago
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Please be quick, i need this as soon as possible!
dalvyx [7]

Answer:

I’m pretty sure the answer is a

Step-by-step explanation:

7 0
3 years ago
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In the rhombus, angle 1 = 10x, angle 2 = x + y, and angle 3 = 15z. Find the value of each variable. 2 1​
cupoosta [38]

The values of the variables x, y and z are; 9, 81 and 6 respectively

<h3>Rhombus Diagonals</h3>

According to the question;

  • All sides of the Rhombus are equal.

Hence, the Diagonals of the Rhombus are perpendicular bisectors of each other.

Therefore,

Angles 1, 2 and 3 are all equal to 90°, so that we have;

  • 10x = 90°

x = 9°

  • x + y = 90, where x=9

  • 9 + y = 90

y = 81°

  • 15z = 90

z = 6°

Read more on Rhombus Diagonals;

brainly.com/question/20627264

8 0
2 years ago
(6a^-4b^2)^-2 for the ^ it is an exponent,
larisa [96]

Negative exponents work the same as positive ones, except you have to consider the inverse of the base.

So, if for example 4^3 = 64, in the same fashion you have

4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{64}

So, negative exponents lead to a fraction with numerator 1 and denominator the same expression, but with positive exponent.

So, in your case, let's work with the inner parenthesis first:

6a^{-4}b^2 = 6 \dfrac{1}{a^4}b^2 = \dfrac{6b^2}{a^4}

Now, if we want to raise this to the negative two, we have

\left(\dfrac{6b^2}{a^4}\right)^{-2} = \dfrac{1}{\left(\frac{6b^2}{a^4}\right)^2}} = \dfrac{1}{\frac{36b^4}{a^8}} = \dfrac{a^8}{36b^4}

4 0
3 years ago
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