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lapo4ka [179]
2 years ago
10

Margaret drove to a business appointment at 30 mph. Her average speed on the return trip was 20 mph. The return trip took

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

Margaret drove 30 miles one way and 30 miles back, totaling 60 miles.

Given that Margaret drove to a business appointment at 30 mph, and her average speed on the return trip was 20 mph, and the return trip took 1/2 hr longer because of heavy traffic, to determine how far did she travel to the appointment the following calculation must be performed:

  • 30 - 20 = 10
  • 10 = 0.5 hours = 30 minutes
  • 30 = 1
  • 20 = 0.666
  • 1 = 1
  • 1.333 = 1.5
  • 1 = 30 x 2 = 60

Therefore, Margaret drove 30 miles one way and 30 miles back, totaling 60 miles.

Learn more in brainly.com/question/24268730

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A tower stand on a horizontal plane. P is the top and Q is the bottom of the tower. A and B are two points on this plane such th
pochemuha

Answer:

32√5

Step-by-step explanation:

We have the right triangles PQA and PQB as well as the given right triangle QAB.

cot(PAQ) = 2/5 = QA/PQ

cot(PBQ) = 3/5 = QB/PQ

cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3

cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB

QA / QB = 2/3

QA = (2/3) QB

QB = (3/2) QA

By the Pythagorean Theorem we have:

(QA)² + 32² = (QB)²

(QA)² + 32² = (3/2 QA)²

(QA)² + 1024 = (9/4) (QA)²

(5/4) (QA)² = 1024

(QA)² = (4/5)1024 = 4096/5

QA = 64/√5

Solve for PQ.

cot(PAQ) = QA/PQ

PQ = QA / cot(PAQ)

PQ = (64/√5) / (2/5) = 32√5

The height of the tower is 32√5.

7 0
3 years ago
Solve the system of equations
rewona [7]

Answer:

x = 1/4

y = -1/2

z = 9/4

Step-by-step explanation:

Here we have a system of 3 equations with 3 variables:

4*x + 2*y + 1 = 1

2*x - y = 1

x + 3*y + z = 1

The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:

2*x - y = 1

2*x - 1 = y

Now that we have an expression equivalent to "y", we can replace this in the other two equations:

4*x + 2*(2*x - 1) + 1 = 1

x + 3*(2*x - 1) + z = 1

Now let's simplify these two equations:

8*x - 1 = 1

7*x - 3 + z = 1

Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:

8*x - 1 = 1

8*x = 1 + 1 = 2

x = 2/8 = 1/4

Now that we know the value of x, we can replace this in the other equation to find the value of z.

7*(1/4) -3 + z = 1

7/4 - 3 + z = 1

z = 1 + 3 - 7/4

z = 4 - 7/4

z = 16/4 - 7/4 = 9/4

z = 9/4

Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:

y = 2*(1/4) - 1

y = 2/4 - 1

y = 1/2 - 1

y = -1/2

Then the solution is:

x = 1/4

y = -1/2

z = 9/4

7 0
3 years ago
Given:
Molodets [167]

Answer:

Third one

<1 = <4 and <2 = <3

Step-by-step explanation:

When two parallel lines form a Z shape, we call the angles at the vertices of Z to be alternate interior angles, which are equal

5 0
3 years ago
Laura lives 15 miles east of Kevin’s place. Kevin lives 8 miles south of Michelle’s place. How far does Michelle live from Laura
My name is Ann [436]

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi)  =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

D = \sqrt{(a - c)^2 + (b - d)^2}

Then the distance between  (-15mi, 8mi) and (0mi, 0mi) is:

D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi

The correct option is the first one, 17 miles.

6 0
3 years ago
Find the distance between the points (3,2) and (8,10)
nadezda [96]

Answer:

8/5

Step-by-step explanation:

(y2-y1) / (x2-x1)

10-2 = 8

8-3 = 5

8/5

6 0
2 years ago
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