H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer : -2 +5G
Hopefully this is right
Answer:
8.2
Step-by-step explanation:
let me know if its wrong
Answer: 7
Step-by-step explanation:
14*1=14
14/2=7
Answer:
<u>XZ = 25</u>
<u>X</u><u>Y = 5</u>
Step-by-step explanation:
XZ = XY + YZ
XZ = (1/5XZ) + 20
XZ - (1/5XZ )= 20
4/5 XZ = 20
5/5 XZ = (20 ÷ 4) × 5
XZ = <u>25</u>
XY = 1/5 × 25
= <u>5</u>
