What you want to do for each of those is follow the formula, y-y[1]=m(x-x[1]). When I say y[1] and x[1], I mean the x and y values given. So the first one would be y-4=-3(x-(-1)). Then you solve for y by distributing the -3 to x and +1 (+1 because two negatives make a positive), making the equation
y-4=-3x-3. Then you subtract the 4. Answer #1. y=-3x-7.
#2.
y-1=1(x-4)
y-1=x-4
y=x-5
#3.
y-2=2(x-(-1))
y-2=2x+2
y=2x+4
Hope this helped you!
Answer:
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Step-by-step explanation:
3 → 13 − 16
![\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BNumber%5C%3Aof%5C%3Adesired%5C%3A%5Bfavourable%5D%5C%3Aoutcomes%7D%7BTotal%5C%3Anumber%5C%3Aof%5C%3Apossible%5C%3Aoutcomes%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B3%7D%7B12%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20%3D%2025%5C%25)
I am joyous to assist you anytime.
We start as 4 8 12 16 20 24that are all divided into the fourth
By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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