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3 years ago

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0 Xa The owner of a large electronic store building wants to install air-conditioning. The size of the air condicioner depends o

n the capacity of the building Below is a diagram with the dimensions of the building. The diagram is not drawn to scale. Notes canst out of a rectangular prism and a triangular prism Calculate the volume of the building

1 answer:

Softa [21]3 years ago

6 0

The volume of a shape is the amount of space in it.

<em>The volume of the building is </em> $180m^3$ <em />

The given parameters are:

<u>Rectangular prism</u>

<u /> $Length = 3m; Width = 8m; Height = 5m$ <u />

<u />

<u>Triangular Prism</u>

<u /> $Base = 3m; Horizontal\ Height= 8m; Vertical\ Height = 5m$ <u />

<u />

<u />

The volume of the rectangular prism is:

<u /> $V_1 = Length \times Width \times Height$ <u />

<u /> $V_1 = 3m \times 8m \times 5m$ <u />

<u /> $V_1 = 120m^3$ <u />

<u />

<u />

The volume of the triangular prism is:

<u /> $V_2 = \frac 12 \times Base \times Horzontal \times Vertical\ Height$ <u />

<u /> $V_2 = \frac 12 \times 3m \times 8m \times 5m$ <u />

<u /> $V_2 =60m^3$ <u />

<u />

So, the volume of the building is:

$V = V_1 + V_2$

$V = 120m^3 + 60m^3$

$V = 180m^3$

Hence, the volume of the building is $180m^3$

Read more about volumes at:

brainly.com/question/15861918

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Two factories I and II produce phones for brand ABC. Factory I produces 60% of all ABC phones, and factory II produces 40%. 10%

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Answer:

0.3721 or 37.21%

Step-by-step explanation:

P(I) = 0.60; P(II) = 0.40;

P(not defective I) = 0.90; P(not defective II) = 0.80

The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

$P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%$

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Which of the following is an equation of a line perpendicular to the equation

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2 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

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3 years ago

In the adjoining figure, the parallel lines are marked by arrow lines. The value of angle 1 is:

dlinn [17]

Answer:

20°

Step-by-step explanation:

40°, 70° and 90° are the measures of the three angles of the quadrilateral.

Measure of fourth angle of the Quadrilateral

= 360° - (40° + 70° + 90°)

= 360° - 200°

= 160°

Measure of angle 1 will be equal to the measure of the linear pair angle of 160° as they are corresponding angles.

Thus,

$m\angle 1 = 180\degree- 160\degree$

$\implies\huge\purple{\boxed{ m\angle 1 = 20\degree}}$

Alternate method:

$m\angle 1 = 180\degree- [360\degree-(40\degree+70\degree+90\degree)]$

$\implies m\angle 1 = 180\degree- [360\degree-200\degree]$

$\implies m\angle 1 = 180\degree- 160\degree$

$\implies m\angle 1 = 20\degree$

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2 years ago

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