Answer:
1: C. $3,474.38
2: B. $44.10
C: C. $570
Step-by-step explanation:
1.
4250 - (4250 x 0.25)
3187.50
3187.50 + (3187.50 x 0.09)
3474.375 which rounds up to
$3,474.38
2.
52 - (52 x 0.2)
41.6
41.6 + (41.6 x 0.06)
44.096 which rounds up to
44.10
3.
500 + (500 x 0.2)
600
600 - (600 x 0.05)
570
Answer:
the first term is a1
the distance between the numbers is d
we have:
a5 = a1 + 4d = 23
a12 = a1 + 11d = 72
so we have the equation:
a1 + 4d = 23
a1 + 11d = 72
=> a1 = -5
d = 7
=> an = -5 + 7(n - 1) = 7n - 12
with an = 7n - 12
=> a2 = 2
a3 = 9
so the first three terms is -5; 2; 9
Answer:
Proved
Step-by-step explanation:
I am going to pose c as the largest side in a random triangle
If so then remember that, by the triangle inequality, a + b > c. Let's start from there...
Statement: | Reasoning:
1. a + b > c 1. Triangle Inequality
2. a + b + c > c + c (adding c on both sides), 2. Algebra + Def. Of Perimeter
a + b + c > 2c (simplified)
Perimeter > 2c (definition of perimeter)
c < 1/2 * Perimeter
Answer:
≈ -5.1857
≈ -5.4857
≈ 3.7262
Step-by-step explanation:
Rewrite the equation system as:
Now, write the system in its augmented matrix form:
![\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%268%260%26-75%5C%5C-3%266%266%265%5C%5C2%26-9%260%2639%5Cend%7Barray%7D%5Cright%5D)
applying row reduction process to its associated augmented matrix:
Swap R1 and R3, and then Swap R1 and R2:
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C6%268%260%26-75%5Cend%7Barray%7D%5Cright%5D)
R3+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
3R2+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
15R3+20R2
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%260%26420%261565%5Cend%7Barray%7D%5Cright%5D)
Now we have a simplified system:
From (3):
(4)
Replacing (4) in (2)
(5)
Finally replacing (5) and (4) in (1)
Answer:
c
Step-by-step explanation:
3 and 3/7 ok hope it helps
