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Reptile [31]
3 years ago
11

PLEAAASEEEE FOR THE LOVE OF GOD for f(x) = 5 - 2 (x + 4)^2 find f (2a -1)

Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

Hi

f(x)= x^2-2x+4

f(2a)= (2a)^2-2(2a)+4 = 4a^2-4a + 4 = 4(a^2-a+1)  

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(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

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so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

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Recall the double angle identity for cosine,

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