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3 years ago

PLEAAASEEEE FOR THE LOVE OF GOD for f(x) = 5 - 2 (x + 4)^2 find f (2a -1)

Mathematics

1 answer:

const2013 [10]3 years ago

6 0

Answer:

f(x)= x^2-2x+4

f(2a)= (2a)^2-2(2a)+4 = 4a^2-4a + 4 = 4(a^2-a+1)

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3 years ago

2x^2+3x-2, a=0 How do I find the derivative?

Ghella [55]

You can use the definition:

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h$

Then if

$f(x) = 2x^2+3x-2$

we have

$f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2$

Then the derivative is

$\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}$

I'm guessing the second part of the question asks you to find the tangent line to f(x) at the point a = 0. The slope of the tangent line to this point is

$f'(0) = 4(0) + 3 = 3$

and when a = 0, we have f(a) = f (0) = -2, so the graph of f(x) passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

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3 years ago

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Answer:

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3 years ago

What is the answer to -12 = 4(f - 6)

TiliK225 [7]

Answer:

f= 3

Step-by-step explanation:

-12 = 4f-24

+24. +24

----------------

12 = 4f

/4. /4

-----------

f= 3

8 0

3 years ago

Read 2 more answers