F(x)=x^5+(x+3)^2 which value completed the table
1 answer:
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Simplify both sides if needed. The left-hand side needs simplification.
4(x - 6)
-2x + 6
4x - 24 -2x + 6
All is left to do is add and subtract to get the x variable all alone.
4x - 24 -2x + 6
6x - 24 6 <-- Add 2x to both sides
6x 30 <-- Add 24 to both sides
x 5 <-- Divide both sides by 6
In order to be in the solution set, x has to be less than or equal to 5.
In interval notation: [5, -∞)
4(x - 6)
4x - 24
All is left to do is add and subtract to get the x variable all alone.
4x - 24
6x - 24
6x
x
In order to be in the solution set, x has to be less than or equal to 5.
In interval notation: [5, -∞)