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2 years ago

F(x)=x^5+(x+3)^2 which value completed the table

Mathematics

1 answer:

galben [10]2 years ago

3 0

Answer:

three boys shared D 10,500.00 in the ratio 6:7:8.find the largest share.

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F(x) = 15x3 + 29x2 + 6x – 8

kirill115 [55]

Answer: whats the question

Step-by-step explanation:

4 0

3 years ago

Write the two conditional statements that make up the following biconditional.

Yuri [45]

The correct answer is A. <span>If I drink juice, then it is breakfast time.
If it is breakfast time, then I drink juice.

This answer is an if-and-only-if conditional statement.
The other options are not.</span>

7 0

3 years ago

Read 2 more answers

Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so

xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

$\frac{5}{8}$ ÷ $\frac{3}{4}$

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

$\frac{5}{8}$ ÷ $\frac{3}{4}=\frac{5}{8}$ × $\frac{4}{3} =\frac{20}{24}$

If we simplify this last expression we have:

$\frac{20}{24}=\frac{10}{12} =\frac{5}{6}$

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

What is 4/7 times 5/p

Phantasy [73]

Answer:

p = 35/4 = 8.750

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

4/7-(5/p)=0

6 0

3 years ago