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Veseljchak [2.6K]
3 years ago
12

The maximum weight for a basketball is 22 9/10 . For a baseball it is 5 1/2 ounces and for a tennis ball it is 2 1/16 ounces . H

ow much heavier is a maximum weight basketball than a maximum -weight baseball?
Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

17 2/5 ounces

Step-by-step explanation:

22 9/10 - 5 1/2 = 17 (9-5)/10

17 4/10 = 17 2/5

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anonymous anonymous 3 years ago On October 2,1991 the Japanese yen was worth .0075 united states dollars. at that time, how much
tiny-mole [99]
1 yen = 0.0075 dollar
450 yen = 0.0075 x 450 = $3.375
3 0
3 years ago
9^x=1/3<br><br> How much is x?
kumpel [21]

Answer:

x = -1/2

Step-by-step explanation:

This question can be solved by applying the laws of indices

In a^n, a - base

n - index

Given

9^x = 1/3

According to the laws of indices, a/b = b^(-a)

Hence we can write, 1/3 = 3^(-1)

9^x = 3^(2x)

Again according to the laws of indices,

a^b = a^n can be written as;

b = n

That is, if in an equation the bases are the same, the indices are also equal.

So we can write,

3^(2x) = 3^(-1)

2x = -1

Divide both sides of the equation by 2, the coefficient of x

2x/2 = -1/2

x = -1/2

6 0
3 years ago
Can someone help me with this?
Vinil7 [7]
U can refer to the picture that I’ve attach below

8 0
2 years ago
Is X-13=x+1 true or false
Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

x-13=x+1

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

x-13+(13)=x+1+(13)\\\\x=x+14

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

x-(x)=x+14-(x)\\\\0=14\ (FALSE)

Therefore, as you can observe, the given equation has no solutions.

3 0
3 years ago
Please help ASAP !!! Thank you !
snow_tiger [21]
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>

<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>

<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>

<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>

8 0
3 years ago
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