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Julli [10]
3 years ago
5

I need help on this lol

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

terms: 3x, 5, 2x, & x

like terms : 3x , 2x , -x

coefficients : 3 , 2

constants : 5

Step-by-step explanation:

coefficients are the numbers next to a variable

Snezhnost [94]3 years ago
6 0
Terms are 3x, 5, 2x, and x.
Like terms are 3x and 2x.
Coefficients are 3 and 2.
Constant is 5.

lmk if anything is incorrect!!
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Item 3
Westkost [7]

Answer:

a = -9

Step-by-step explanation:

a+(-4)=-13

add 4 to each side

a-4+4 = -13+4

a = -9

4 0
3 years ago
Read 2 more answers
In many cases the Law of Sines works perfectly well and returns the correct missing values in a non-right triangle. However, in
Agata [3.3K]

\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}

Considering the diagram. \angle B is shown to be acute, so \boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}.

Angles in a triangle add to 180°, so m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right).

Using the law of cosines,

AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}

3 0
1 year ago
YOU Will be SHOWERED With POINTS IF U HELP ME
Volgvan

Answer: C

<u>Step-by-step explanation:</u>

f(x) = 26.2 - 0.1x

f(100) = 26.2 - 0.1(100)

         = 26.2 = 10.0

         = 16.2

f(5-) = 26.2 - 0.1(50)

       = 26.2 - 5.0

       = 21.2

******************************************************

Answer: D

<u>Step-by-step explanation:</u>

f(x) = 2|x - 3| + 1

2 units right: f(x) = 2|x - (3 + 2)| + 1

                           = 2|x - 5| + 1

3 0
3 years ago
Read 2 more answers
Mammoth Cave in Kentucky has a minimum elevation of-124.1 meters. Suppose a hiker traveled to the bottom of the cave. How many m
strojnjashka [21]

Answer:

they would have traveled 124.1 meters. If you start at 0 elevation (ground level) and you go all the way down then the maximum lowest point he can get to is 124.1m.

7 0
3 years ago
Given the diagram below, how many outputs does the Catwalk Problem have for each positive input value?
Ghella [55]

Answer:

Step-by-step explanation:

for every value of x

,it has two values of y except at extreme values of x,where it has only one value.

4 0
4 years ago
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