Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
A) The given equation has no solution. The absolute value cannot be negative, but must be -9 in order for the equation to be satisfied.
b) |x -7| = 2 . . . . . . . the equation
Solution 1:
-2 = x -7
5 = x . . . . . . add 7
Solution 2
x -7 = 2
x = 9 . . . . . . add 7
The two numbers are {5, 9}
Answer:
The value of test statistic is 1.338
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 16.000
Sample mean, 
= 16.218
Sample size, n = 22
Alpha, α = 0.05
Sample standard deviation, s = 0.764
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Thus, the value of test statistic is 1.338
Answer:
3 teddy bears for each cookie he has.
Answer:
Answer: 4(x+1) over (x-5)
Step-by-step explanation:
