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nasty-shy [4]
3 years ago
5

Examine the following graph of a line.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0

Answer:

None of these are correct.

Step-by-step explanation:

The real answer would be either y-0 = 1/3(x - 2) or y-1 = 1/3(x - 5).

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A bag of skittles candy was found to have 15% of the candies to be red, 15% were orange, 10% yellow and 20% green. The rest were
harkovskaia [24]

It is a very low probability because forty percent is purple

8 0
3 years ago
Why does 843,000 round to 840,000 rather than 850,000 when rounded to the nearest ten thousand
Serjik [45]
Because 843,000 is closer to 840,000 than 850,000
5 0
3 years ago
Read 2 more answers
Please I need this quick!!! 15 points
professor190 [17]
Let the number be n.

Then:

n^2 + (1/n)^2 = 82/9; find n.  Find the LCD; it is 9n^2.

Mult all 3 terms by 9n^2:
                                                                  82*9n^2
9n^4 + 9 = (82/9)(9n^2)  =>    9n^4 + 9 = ------------  
                                                                        9
Then 9n^4 - 82n^2 + 9 = 0

I used my graphing calculator to find that n = 3.  

Let's check:     is 3^2 + (1/3)^2 = 82/9?
                        Is   9   + 1/9 = 82/9?
                        Is  81 + 1 = 82?   YES.  So, n=3 is a solution.

7 0
3 years ago
Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...​
mel-nik [20]

Answer:

a_{n} = 3n + 77

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 80 and d = a₂ - a₁ = 83 - 80 = 3 , then

a_{n} = 80 + 3(n - 1) = 80 + 3n - 3 = 3n + 77

3 0
3 years ago
A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = u_{x} t, where u_{x} is the

   horizontal component of its velocity

∵ u_{x} = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
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