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DiKsa [7]
3 years ago
7

Helen rolls a dice and flips a coin. Calculate the probability that she will get a 4 and a tail.

Mathematics
2 answers:
Rom4ik [11]3 years ago
5 0

Answer:

1/12

Step-by-step explanation:

The probability that Helen will roll a 4 is 1/6 the probability that she will get tails is 1/2. Multiply those two events together to find the probability of P(A and B)

matrenka [14]3 years ago
3 0
1/12!!! she will get 1/12
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Write 1/10^2 using exponents
Viefleur [7K]

Answer:

I think it would be 100

Step-by-step explanation:

because 10^2 is 10 x 10 which equals 100 and so if you have 1/10^2 it's basically saying 1 divided by 10^2 and 10^2 is 100 so it would be 1 divided by 100 which equals 100.

I hope this helped any.

4 0
4 years ago
F(1) = 4, f(n) = f(n<br> − 1) + 11
zvonat [6]

Answer:

Step-by-step explanation:

You don't specify what you're supposed to do, so I'll make an educated guess.  

Given the sequence f(1) = 4, f(n) = f(n  − 1) + 11, find the first 5 terms:

f(1) = 4

f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15

f(3) = f(2) + 11 = 15 + 11 = 26

f(4) = f(3) + 11 = 26 + 11 = 37

f(5) = 37 + 11 = 48

4 0
3 years ago
Find the area of this triangle​
creativ13 [48]

Answer:

The area should be 170

Step-by-step explanation:

L× W =70×10=170

5 0
3 years ago
What is the perimeter of the rectangle? Write your answer in scientific notation. The area is 2.76 x 10 pw12
MrRa [10]
We know that
area of a rectangle=length*width
length=area/width
area=2.76 x 10^12 units²<span>
width=4.6 x 10</span><span>^5 units
</span>length=2.76 x 10^12/4.6 x 10^5 ------> 6 x 10^6 units

perimeter of a rectangle=2*[length+width]
width=4.6 x 10^5 units----> is equal to 0.46 x 10^6 units
length=6 x 10^6 units

perimeter of a rectangle=2*[6x10^6+0.46x10^6]----> 12.92 x 10^6 units

the answer is
12.92 x 10^6 units

5 0
3 years ago
2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
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