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Anastaziya [24]
3 years ago
8

50 points for this worksheet

Physics
2 answers:
mrs_skeptik [129]3 years ago
8 0

I KNOW THIS ONE I DID IT LIKE LAST YEAR I CAN HELP!!!!

Kazeer [188]3 years ago
3 0

Answer:

that is so easy I can help

Explanation:

hmmmmmmmmmmmmm

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What is the net force of a falling bowling ball that weighs 55 N and has 15 N of air resistance?
serg [7]

its 55 :) have a great day queen/king/whatever gender you are

3 0
3 years ago
Read 2 more answers
You exit the Vet's Office.
kifflom [539]

(1) When you exit the office, your position is 60.8 m and the total distance traveled is 60.8 m.

(2) When you walk to the bank, your position is 60.8 m, displacement is 0 and the total distance traveled is 121.6 m.

(3) When you walk to flower shop, your position is 26.9 m, displacement is 0 and the total distance traveled is 148.5 m.

(4) When you walk to the Vet's Office, your position is 60.8 m, displacement is 60.8 m and the total distance traveled is 182.4 m.

<h3>You exit the Vet's Office</h3>

When you exit the Vet's Office, your position is 60.8 m (assuming your starting position is the bank).

The total distance have you travelled = 26.9 m + 33.9 m = 60.8 m

<h3>You walk to the Bank</h3>

your new position is 60.8 m

your displacement = 60.8 m - 60.8 m = 0 (assuming your starting position is the bank)

total distance have you travelled = 60.8 m +  60.8 m = 121.6 m

<h3>You walk to the Flower Shop</h3>

your new position is 26.9 m

your total displacement = 0 + 26.9 m = 26.9 m

total distance have you travelled = 26.9 m + 121.6 m = 148.5 m

<h3>You walk to the Vet's Office</h3>

your new position is 26.9 m + 33.9 m = 60.8 m

your total displacement = 26.9 m + 33.9 m = 60.8 m

total distance have you travelled = 148.5 m + 33.9 m = 182.4 m

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

5 0
2 years ago
You have a light spring which obeys Hooke's law. This spring stretches 2.92 cm vertically when a 2.70 kg object is suspended fro
ehidna [41]

(a) 907.5 N/m

The force applied to the spring is equal to the weight of the object suspended on it, so:

F=mg=(2.70 kg)(9.8 m/s^2)=26.5 N

The spring obeys Hook's law:

F=k\Delta x

where k is the spring constant and \Delta x is the stretching of the spring. Since we know \Delta x=2.92 cm=0.0292 m, we can re-arrange the equation to find the spring constant:

k=\frac{F}{\Delta x}=\frac{26.5 N}{0.0292 m}=907.5 N/m

(b) 1.45 cm

In this second case, the force applied to the spring will be different, since the weight of the new object is different:

F=mg=(1.35 kg)(9.8 m/s^2)=13.2 N

So, by applying Hook's law again, we can find the new stretching of the spring (using the value of the spring constant that we found in the previous part):

\Delta x=\frac{F}{k}=\frac{13.2 N}{907.5 N/m}=0.0145 m=1.45 cm

(c) 3.5 J

The amount of work that must be done to stretch the string by a distance \Delta x is equal to the elastic potential energy stored by the spring, given by:

W=U=\frac{1}{2}k\Delta x^2

Substituting k=907.5 N/m and \Delta x=8.80 cm=0.088 m, we find the amount of work that must be done:

W=\frac{1}{2}(907.5 N/m)(0.088 m)^2=3.5 J

5 0
3 years ago
A standard steel pipe (D = 3.81 in.; d = 3.24 in.) supports a concentrated load of P = 930 lb. The span length of the cantilever
Maurinko [17]

Answer:

a) τmax = 586.78 P.S.I.

b) σmax = 15942.23 P.S.I

Explanation:

D = 3.81 in

d = 3.24 in

P = 930 lb

L = 3.7 ft = 44.4 in

a) The maximum horizontal shear stress can be obtained as follows

τ = V*Q / (t*I)

where

V = P = 930 lb

Q = (2/3)*(R³- r³) = (1/12)*(D³- d³) = (1/12)*((3.81 in)³- (3.24 in)³)

⇒ Q = 1.7745 in³

t = D - d = 3.81 in - 3.24 in = 0.57 in

I = (π/64)*(D⁴-d⁴) = (π/64)*((3.81 in)⁴- (3.24 in)⁴) = 4.9341 in⁴

then

τ = (930 lb)*(1.7745 in³) / (0.57 in*4.9341 in⁴)

⇒ τmax = 586.78 P.S.I.

b) We can apply the following equation in order to get the maximum tension bending stress in the pipe

σmax = Mmax *y / I

where

Mmax = P*L = 930 lb*44.4 in = 41292 lb-in

y = D/2 = 3.81 in /2 = 1.905 in

I = 4.9341 in⁴

then

σmax = (41292 lb-in)*(1.905 in) / (4.9341 in⁴) = 15942.23 P.S.I

6 0
4 years ago
A loop with a break in it that prevents current from flowing is called a(n)_______<br> circuit.
Annette [7]

Answer:

an open circuit

Explanation:

7 0
4 years ago
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