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Savatey [412]
3 years ago
13

How much heat is absorbed by 3 kg honey baked ham as energy from the oven causes its temperature to change from 10°C to 60°C? (S

pecific heat capacity of ham 3287 cal/kgºC)?
Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

The answer is 493.05kJ

Explanation:

given

mass m= 3kg

t1=  10°C

t2= 60°C

Specific heat capacity of ham =3287 cal/kgºC

Required,

The quantity of heat, Q

Step two:

the formula is

Q= mcΔT

substitute

Q= 3*3287(60-10)

Q=9861*50

Q=493050 J

Q= 493.05kJ

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A concave mirror has a radius of curvature of 1.6m. Find the focal length
Yuki888 [10]
Given,

Radius of curvature of concave mirror = 1.6m

We know that ,

Focal length = radius/2

Hence ,

Focal length of concave mirror = radius of concave mirror /2

=> F = 1.6/2

=> F = 0.8m

Hence the focal length of concave mirror is 0.8 m
5 0
2 years ago
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What is the speed of sound in dry air if the temperature is 46°C?
maria [59]
The speed of sound at 46 C is 800.91 mph
7 0
3 years ago
A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajector
Pavlova-9 [17]

Answer:

v=7905m/s

t=5063s

Explanation:

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6370 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth?

The weight of the satellite is the centripetal force, so:

W=mg=F_{cp}=ma_{cp}=m\frac{v^2}{r}

Which means: g=\frac{v^2}{r}

We can calculate then the velocity:

v=\sqrt{gr}=\sqrt{(9.81m/s^2)(6370000m)}=7905m/s

For calculating how long will it take for the satellite to complete one trip around Earth we consider that the distance of the trip is the circumference of the orbit. This is calculated as C=2\pi r.

Since velocity is v=d/t, we have:

t=d/v=C/v=2\pi r/v=\frac{2\pi 6370000}{7905m/s} =5063s

5 0
3 years ago
Which one is the full moon?​
Svetlanka [38]

Answer:

The one to the left

Explanation:

6 0
3 years ago
A simple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium posit
solniwko [45]

Answer:

a)   T = 2.997 s

b)   K = 14.3 J

c)   φ = 0.444 rad

Explanation:

a) Determine its period

  The pendulum simple’s period is:

 

  T = 2π\sqrt{\frac{l}{g} }

        Where l: Pendulum’s length

                    g = 9.8 m/s2

  T = 2π\sqrt{\frac{2.23}{9.8} }

  T = 2.997 s

b) Total energy

  Initially his total energy is kinetic

  K = \frac{mv^{2} }{2}

  K = \frac{(6.74)(2.06)^{2} }{2}

  K = 14.3 J

c) Maximum angular displacement

  φ = cos^{-1}(1-\frac{E}{mgl} )

  φ = cos^{-1}(1-\frac{14.3}{(6.74)(9.8)(2.23)} )

  φ = 0.444 rad

4 0
3 years ago
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