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mel-nik [20]
2 years ago
5

You place a 3.0-m-long board symmetrically across a 0.5-m-wide chair to seat three physics students at a party at your house. If

60-kg Dan sits on the left end of the board and 50-kg Tahreen on the right end of the board, where should 54-kg Komila sit to keep the board stable? Ignore the mass of the board and treat each student as point-like objects The positive r-direction is to the right, and the origin is at the center of the chair
Part A Determine the coordinate of the leftmost point on the board where Komila can sit to keep the board stable
Part B Determine the coordinate of the rightmost point on the board where Komila can sit to keep the board stable

Physics
1 answer:
kakasveta [241]2 years ago
5 0

Answer:

A) for leftmost point the coordinate is -0.28m that means it should be 0.28m towards the right.

B) for rightmost case the coordinate is 0.28m which is where komila should sit.

Explanation:

Detailed calculation and explanation is shown in the image below

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A geologist sees a fault along which blocks of rock in the footwall have moved higher relative to blocks of rock in the hanging
Luda [366]

Answer: Normal fault

Explanation:

The type of fault that is explained above is a normal fault. We should note that normal faults typically takes place in a divergent boundary in a scenario where the crusts may have been pulled apart.

Since the crust is pulled apart in this case, it leads to the downward movement of the hanging wall which leads to the football being above the hanging wall.

6 0
3 years ago
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
kari74 [83]

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

8 0
3 years ago
Solve the equation below for vi.<br> d=vit +.5at2
Andrej [43]

Answer:  \dfrac{d-0.5at^2}{t}=v_i

<u>Explanation:</u>

d=v_it+0.5at^2\\\\\\\text{Subtract}\ 0.5at^2\ \text {from both sides:}\\d-0.5at^2=v_it\\\\\\\text{Divide both sides by t:}\\\dfrac{d-0.5at^2}{t}=v_i

8 0
3 years ago
What is a force on the object if it has a mass of 10.41 kg and an acceleration of 6.5 m/s2
Fudgin [204]
To determine the force of the system, we use Newton's Second Law of motion which relates force and mass where they are directly proportional and the constant of proportionality is the acceleration. We calculate as follows:

F = ma
F = 10.41 kg ( 6.5 m/s^2 )
F = 67.67 kg m / s^2 or N
4 0
2 years ago
Mr. Cohen is a scientist who is testing the efficiency of a 9 V battery by measuring how much electrical energy it releases. He
Mashcka [7]

Answer:

D. (7 ÷ 9) × 100

Explanation:

In order to solve this problem we need the answers of the problem, performing an internet search this problem is found, with the different answer options

A. (7 − 9) × 100

B. (9 − 7) × 100

C. (9 ÷ 7) × 100

D. (7 ÷ 9) × 100

Returning to the problem of the total energy of 9V only 7 volts were used. If we make a rule of three we realize that:

100 = 9V\\x  = 7\\x = \frac{7*100}{9} \\

x = 77.77%

In this way we determine that the answer is D.

5 0
2 years ago
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