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2 years ago

9. Change the given equation to the form y = mx + b. Give the values of b and m.

1 answer:

8 0

X+4y=16
subtract x
4y = -x+16
divide 4 from 4y and divide by 4 on other side too
(4y/4) = (-x/4) + (16/4)

y=-1/4x+4
M=-1/4
B=4

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WILL GET BRAILIEST FOR CORRECT ANSWER

Alex Ar [27]

Answer:

x = ± $\sqrt{20}$

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± $\sqrt{20}$

which can be simplified to

x = ± 2 $\sqrt{5}$

[ ± means plus or minus ]

5 0

3 years ago

One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on

irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna = 237.08 ft

Step-by-step explanation:

The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°

distance from her position to the top of the building = 2475 ft

distance from her position to the top of the flag = 2615 ft

(a) How far away from the base of the building is the surveyor located?

using the SOHCAHTOA principle

cos 34° = c/2475

c = 0.8290375726 × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b = 0.5591929035 × 2475

b = 1384.0024361

b = 1384.00 ft

(c) What is the angle of elevation from the surveyor to the top of the antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ = 0.784665392

∅ = cos-1 0.784665392

∅ = 38.310258303

∅ = 38.31°

(d) How tall is the antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) = 0.6199159917 × 2615

(a + b) = 1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00 = 237.08031822 ft

Height of antenna = 237.08 ft

8 0

3 years ago

Write an equation of a line that is parallel to y = 3x – 5 and goes through the point (3, 1).

scoray [572]

Paralell means has same lsope
y=mx+b
m=slope

given
y=3x-5
slope=3

y=3x+b
find b
(3,1)
x=3
y=1
sub and find b

1=3(3)+b
1=9+b
minus 9 both sides
-8=b

y=3x-8 is equation

5 0

3 years ago

Assume that all triangles have interior angles less than 90°.A surveyor sights on a survey marker that is 132.3m distant. She ne

Vadim26 [7]

Answer:

85.9 m

Step-by-step explanation:

The law of sines can help figure this.

The remaining angle in the triangle is ...

180° -75° -68° = 37°

This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...

b/sin(B) = c/sin(C)

b = sin(B)·c/sin(C) = 132.3·sin(37°)/sin(68°) ≈ 85.873 . . . meters

The surveyor is about 85.9 meters from the second marker.

4 0

3 years ago

A kitchen measures 3.75 meters by 4.2 meters.

dalvyx [7]

Answer:

a. $A_{(kitchen)}=15.75\ m^2$

b. $A_{(total)}=39.375\ m^2$

Step-by-step explanation:

The formula for calculate the area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width

a. We know that the kitchen measures 3.75 meters by 4.2 meters; then we can say that:

$l=3.75\ m\\\\w=4.2\ m$

Therefore, substituting these values into the formula, we get that the area of the kitchen is:

$A_{(kitchen)}=(3.75\ m)(4.2\ m)=15.75\ m^2$

b. The area of the living room is one and a half times (1.5 times) that of the kitchen, this is:

$A_{(living)}=(1.5)(15.75\ m)=23.625\ m^2$

Therefore, the total of the living room and the kitchen is:

$A_{(total)}=15.75\ m^2+23.625\ m^2=39.375\ m^2$

3 0

3 years ago