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Crazy boy [7]
2 years ago
5

You have $50 and are buying some movies on DVDs that cost $15 each. Write an expression that shows how

Mathematics
1 answer:
alexdok [17]2 years ago
3 0

Answer:

50 - 15m

Step-by-step explanation:

You start out with 50 dollars so that is the constant.

Each DVD is 15 dollars, so for every dvd(m) it is 15 dollars.

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If f (x) = x2 + 4x-12. find f(2).
Otrada [13]

Answer:

f=  x^2+4x−12 /x

Step-by-step explanation:

Step 1: Divide both sides by x.

fx /x  =  x^2+4x−12 /x

f=  x^2+4x−12 /x

6 0
3 years ago
rita reads 3 fiction books for every 2 non-fiction books.Which ratio represents the number of non-fiction books rita has read wh
Fudgin [204]

Answer:

6 nonfiction books

Step-by-step explanation:

if it's fiction to non 9:6

if it's non to fiction 6:9

(you may need to simplify)

5 0
3 years ago
A line passes through the points (4, -1) and (2,3). What is the slope of the line?
sveticcg [70]

Answer:

-2

Step-by-step explanation:

image attached!

7 0
3 years ago
WILL GIVE BRAINLIST
Nataliya [291]

Answer:

Step-by-step explanation:

Find out the  how much chlorine is in the pool .

To prove

As given

The amount of chlorine in a swimming pool varies directly with the volume of water.

The pool has 2.5 milligrams of chlorine per liter of water.

i.e

2.5 milligrams of chorine = 1 litre of water

There are 8000 gallons of water in the swimming pool.

As 1 gallons = 3.78541 litre (Approx)

Now convert 8000 gallons of water in litres.

8000 gallons = 8000 × 3.78541 litre

                     = 30283.28 litres

Now calculate chlorine in the pool for 30283.28 litres  of waters.

As

2.5 milligrams of chlorine = 1 litre of water

2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water

75708.2 milligrams of chlorine for 30283.28 litre of water .

5 0
2 years ago
Read 2 more answers
Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the
denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let \mu = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, H_0 : \mu = 2,000 psi       {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, H_A : \mu < 2,000 psi      {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = ample mean strength = 1,997.2956 psi

            \sigma = population standard devaition = 10 psi

            n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO,  T.S. < -1.645   {then reject null hypothesis}

         \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645

         \frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645

         (\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645

          -0.27044 \times \sqrt{n}< -1.645

               \sqrt{n}> \frac{-1.645}{-0.27044}

                 \sqrt{n}>6.083

                  n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0
4 years ago
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