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3 years ago

Find the slope of the line that goes through (0, 2) and (4, −2).

2 answers:

5 0

M = (y2 - y1) / (x2 - x1)

m = (-2 - 2) / (4 - 0)

m = -4 / 4

m = -1

The slope of the line that goes through (0, 2) and (4, -2) is -1.

mojhsa [17]3 years ago

5 0

Answer: -1

Step-by-step explanation:

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John is 12 years older than Myles. 5 Years ago John was 2 times as old as Myles. How old are john and Myles now

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Answer:

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Step-by-step explanation:

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2 years ago

Select all the points that are on the graph of the line 2x + 4y=20 a.)(0.5) b. (0,10) c. (1,2) d.) (1,4) e.) (5,0) f. (10,0)

zmey [24]

Answer:

(0,5) and (10,0)

Step-by-step explanation:

The equation of the straight line is given by 2x + 4y = 20 .......... (1)

Now, point (0,5) satisfies the equation (1) as putting x = 0, we will get y = 5.

Now, point (0,10) does not satisfy the equation (1) as putiing x = 0, we get y = 5 ≠ 10

Again, point (1,2) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 2

Now, point (1,4) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 4

Again, point (5,0) does not satisfy the equation (1) as putiing y = 0, we get x = 10 ≠ 5

Finally, point (10,0) satisfies the equation (1) as putiing y = 0, we get x = 10 .

Therefore, only points (0,5) and (10,0) are on the graph of the line 2x + 4y = 20 (Answer)

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3 years ago

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Answer:

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2 years ago

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2 years ago

The face of a clock has a circumference of 63 in. What is the area of the face of the clock?

ryzh [129]

Answer:

The area of the clock $= 315.41\ inch^{2}$

Step-by-step explanation:

We have been given the face of the clock that is $63\ in$

So that is also the circumference of the clock.

Since the clock is circular in shape.

So $2\pi(r)=63\ inch$

From here we will calculate the value of radius $(r)$ of the clock that is circular in shape.

Then $2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in$

Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.

Now $\pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}$

So the area of the face of the clock = $315.41\ in^{2}$

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3 years ago