What is the 6th term of the geometric sequence below?
2 answers:
Answer:
C. 64.
Step-by-step explanation:
The nth term = a1 r^(n-1) where a1 = first term and r = common ratio.
Here a1 = 2 and common ratio r = 4/2 = 2.
6th term = 2(2)^(6-1)
= 2 * 2^5
= 2*32
= 64.
Answer:
C 64
Step-by-step explanation:
We are multiplying by 2 each time
1st term is 2
2*2 =4
2nd term is 4
4*2 =8
3rd term is 8
8*2 =16
4th term is 16
16*2=32
5th term is 32
32*2=64
6th term is 64
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