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3 years ago

What is the 6th term of the geometric sequence below?

Mathematics

2 answers:

Step2247 [10]3 years ago

4 0

Answer:

C. 64.

Step-by-step explanation:

The nth term = a1 r^(n-1) where a1 = first term and r = common ratio.

Here a1 = 2 and common ratio r = 4/2 = 2.

6th term = 2(2)^(6-1)

= 2 * 2^5

= 2*32

= 64.

densk [106]3 years ago

3 0

Answer:

C 64

Step-by-step explanation:

We are multiplying by 2 each time

1st term is 2

2*2 =4

2nd term is 4

4*2 =8

3rd term is 8

8*2 =16

4th term is 16

16*2=32

5th term is 32

32*2=64

6th term is 64

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