There are
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have

The last expression has a more compact form in terms of the so-called multinomial coefficient,

Answer:
3
Step-by-step explanation:
2x^9 = 1
3x^6 = 2
- x - 20 = 3
We know that the perimeter of a rectangle = 2(l + w)
l = length
w = width
In our problem,
l = 5x
w = 5x - 4
Let's create an inequality to help us solve this problem.
2(5x + (5x - 4)) ≥ 96
Let's start off by simplifying the terms inside the parentheses.
2(10x - 4) ≥ 96
Distribute the 2
20x - 8 ≥ 96
Add 8 to both sides.
20x ≥ 104
Divide both sides by 20
x ≥ 5.2
Let's plug 5.2 into x for our length and width.
Length = 5x = 5(5.2) = 26 cm
Width = 5x - 4 = 5(5.2) - 4 = 26 - 4 = 22 cm
The smallest possible dimensions for the rectangle are, length = 26 cm and width = 22 cm
Answer:
8.4 square units
Step-by-step explanation:
See attachment for the figure.
Trigonometric area formula is Area =
Where a and b are two sides of the triangle and C is the angle between these two sides.
Given:
side a = 6 units, c = 2√2 units and ∠B = 80°
Then area of the triangle :
Area = 
= 
= 
= 6√2×sin80°
= 6×(1.414)×0.9848
= 8.36 square units
≈ 8.4 square units
Answer: Please include rest of question
Step-by-step explanation:
Then I’ll be able to answer