Help pls i don’t understand graphs!! <3

kondor19780726 [428]

Answer:b is 16

Step-by-step explanation:a is 15 and c is 17. So what comes in between those numbers, exactly 16

6 0

3 years ago

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that $a = 10400, b = 15400$

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

$P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32$

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

$P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72$

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0

2 years ago

51 is 33 1/3 of what number?

nevsk [136]

Answer:

$\boxed{\frac{153}{100}\:\:Or\:\:1.53}$

Step-by-step explanation:

Let the number be $n$ .

Then,

$33\frac{1}{3} \tmes n=51$

This implies that;

$\frac{100}{3} n=51$

We multiply both sides by $\frac{3}{100}$ to obtain;

$\frac{3}{100} \times \frac{100}{3}n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{153}{100}$

Or

$\Rightarrow n=1.53$

5 0

3 years ago

Read 2 more answers

What are the solutions to the quadratic equation 4x2=64?

Paraphin [41]

X=4 or X=-4 because 4(4)^2 does =64

3 0

3 years ago

Read 2 more answers

How to Become a Millionaire Upon graduating from col- lege, Donna has no initial capital. However, during each year she makes de

lesantik [10]

Answer:

amount is 1000 × $e^{0.08t}$

$40762.20 balance of Donna's account will be 1 million dollars when she retires in 40 years

rate 14.97 % when Donna's account will have a balance of 1 million dollars in 40 years when principal is $2500

Step-by-step explanation:

principal = $1000

rate = 8 % = 0.08

to find out

the future value, S(t)

principal when Donna's account will be 1 million dollars when she retires in 40 year

at what rate Donna's account will have a balance of 1 million dollars in 40 years

solution

we know compounded continuously formula i.e.

amount = principal × $e^{rt}$ ..................1

put the value principal and rate in equation 1 to find amount any time

amount = principal × $e^{rt}$

amount = 1000 × $e^{0.08t}$

in 2nd part we have time 40 year and amount 1 million so put rate amount and time in equation 1 to find principal

rt = 0.08 × 40 = 3.2

amount = principal × $e^{rt}$

1000000 = principal × $e^{3.2}$

principal = 1000000 / $e^{3.2}$

principal = 1000000 / 24.5325302

principal = 40762.20397

so $40762.20 balance of Donna's account will be 1 million dollars when she retires in 40 years

in 3rd part we have amount 1 million and principal $2500 and time 40 year put all these in equation 1 to find rate

amount = principal × $e^{rt}$

1000000 = 2500 × $e^{40r}$

take ln both side

ln $e^{40r}$ = ln (1000000 / 2500 )

40 r = ln 400

r = ln (400) / 40

r = 0.149787

so rate 14.97 % when Donna's account will have a balance of 1 million dollars in 40 years when principal is $2500

5 0

2 years ago