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allsm [11]
3 years ago
15

Please answer correctly and no links

Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

\frac{1}{5}(m - 100)

Step-by-step explanation:

If you multiply out the bracket, you'll get \frac{1}{5}m - 20

Try multiplying out the brackets in the other answers and you'll get something different

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The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets . She can make 1
scoundrel [369]

Answer:

40

Step-by-step explanation:

The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets .

Let n be the number of baskets and let t be the mount of time it takes to make the basket. This means that:

n α t

=> n = kt

where k = constant of proportionality

She can make 4 baskets in every 1/2 hour.

This means that:

4 = k * 1/2

=> k = 4 * 2 = 8 baskets per hour

The time is now 5 hours (t = 5). Therefore:

n = 8 * 5 = 40 baskets

She can make 40 baskets in 5 hours.

8 0
3 years ago
What is this percent of change 40;72
salantis [7]
Given:
Original or base : 40
New amount : 72

We need to find the difference of the new amount and the original amount

72 - 40 = 32

We then divide the difference by the original amount

32/40 = 0.80

We multiply the quotient by 100%

0.80 x 100% = 80%

The percentage of change is 80%
6 0
3 years ago
Hey guys!! U think u can help me? Plss :))
slavikrds [6]

Answer:

A: The plant grows 1CM every day

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(-6time + 3) + (5time -4)
Fynjy0 [20]

Answer:

-2

Step-by-step explanation:

18+-20

-2

3 0
3 years ago
1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
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